An exterior angle of triangle is $80^{\circ}$ and the interior opposite angles are in the ratio $1 : 3$ . The measure of each interior opposite angle is

40^o, 120^o

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20^o, 60^o

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30^o, 60^o

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30^o, 90^o

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Solution

The correct option is B: $20^{\circ}, 60^{\circ}$
Given: Exterior angle $= 80^{\circ}$
Ratio of opposite interior angles $1 : 3$
Let interior opposite angles be $x$ and $3 x .$

Therefore, $x + 3 x = 80^{\circ}$

or, $4 x = 80^{\circ}$

or, $x = 20^{\circ}$

Hence, required angles are $20^{\circ}, 60^{\circ}$

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An exterior angle of a triangle is 80^o and two interior opposite angles are equal. Measure of each of these angle is:

The two interior opposite angles of an exterior angle of a triangle are 60 degree and 80 degree. Find the measure of the exterior angle.

100^{o}

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