An external force $F$ acts horizontally on a box of mass $m$ at a height $h$ . If the $C M$ of the box is situated at a height $c$ , find the:
minimum value of $F$ so as to topple the box.

\frac{m g b}{2 h}

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\frac{m g b}{h}

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\frac{m g b}{3 h}

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\frac{m g b}{4 h}

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Solution

The correct option is A $\frac{m g b}{2 h}$
$\begin{matrix} f o r t o p p l i n g e d g e = 0 \Rightarrow \frac{m g b}{2} = F h \Rightarrow F = \frac{m g b}{2 h} H e n c e, o p t i o n A i s c o r r e c t a n s w e r . \end{matrix}$

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An external force F acts horizontally on a box of mass m at a height h. If the CM of the box is situated at a height c, find the:minimum value of F so as to topple the box.

The correct option is A mgb2hfortopplingedge=0⇒mgb2=Fh⇒F=mgb2hHence,optionAiscorrectanswer.

An external force $F$ acts horizontally on a box of mass $m$ at a height $h$ . If the $C M$ of the box is situated at a height $c$ , find the:
minimum value of $F$ so as to topple the box.

The correct option is A $\frac{m g b}{2 h}$
$\begin{matrix} f o r t o p p l i n g e d g e = 0 \Rightarrow \frac{m g b}{2} = F h \Rightarrow F = \frac{m g b}{2 h} H e n c e, o p t i o n A i s c o r r e c t a n s w e r . \end{matrix}$