Question

an fcc lattice has a lattice parameter a equals to 400 picometre calculate the molar volume of the lattice including all the empty space

Answer 1

Solution : Volume =a^3={400×10^(−12m)^3 =64×10^(−24)cm^3 Vtotal=V*NA ( where NA is avogadro's number) =64×10^(-24)×6.02×10^23 =38.4 Molar Volume = 1/4 * Vtotal =1/4×38.4 =9.6ml