Question

An hour hand of a watch is $2.5cm$ long. What will be the linear speed of a point on hour hand at a distance of $0.5cm$ from the tip?

Answer 1

We know that the angular velocity of an hour hand is $\frac{2\pi }{3600}rad/sec$

And $v=r\omega$

So,the linear speed of a point on hour hand at a distance of 0.5 m from the tip $=r\omega =(2.5-0.5)\times \frac{\pi }{1800}$

$=\frac{\pi }{900}m/s$