Question

An ice berg of density $900kg/m^3$ is floating in water of density $1000kg/m^3$. The percentage of volume of ice-cube outside the water is

• A. $20\%$
• B. $35\%$
• C. $10\%$
• D. $25\%$

Answer 1

Answer: (C)

$10\%$

Let the volume of the cube be $V$ and the fraction of cube outside water be $f$.

Thus, volume of ice inside water $=$ volume of water displaced $=(1-f)V$

Under equilibrium,

Weight of ice $=$ Weight of water displaced

$⟹V{\rho }_{ice}g=(1-f)V{\rho }_{water}g$

$⟹(1-f)=\frac{9}{10}$

$⟹f=\frac{1}{10}$

Thus, the percentage of volume outside water $=10$%