Question

an ice berg of density 900kg/m³ is floating in water of density 1000 kg/m³. the percentage of volume of ice cube outside the water is:-

• 20%
• 35%
• 10%
• 25%

Answer 1

$$\begin{gathered} densit{y}_{ice}=\frac{V_{out}}{V_{tot}}\times densit{y}_{water} \\ 900=\frac{V_{out}}{V_{tot}}\times 1000 \\ {V}_{out}=\frac{900}{1000}\times V_{tot} \\ =\frac{1}{10}\times V_{tot} \\ Sothefractionoficecomingout=\frac{1}{10} \\ \%ofvolumeofice=\frac{1}{10}\times 100=10\% \end{gathered}$$