Question

An ice-cream cone consisting of the cone is surmounted by a hemisphere.The common radius of a hemisphere & cone is $3.5cm$ & the total height of ice cream is $12.5cm$. Calculate the volume of ice-cream in the solid shape .

Answer 1

Radius of cone $=r$ of $h.s$

$r=3.5$

Total height $=12.5$

Total $h$ of cone $-h.s.$

$12.5-3.5$

$h$ of conical $=9cm$

$V$. of ice cream in the cone $=$ volume of conical part $+V.$ of $h.s.$

$=\frac{1}{3}\pi r^{2}h+\frac{2}{3}\pi r^3$

$=\frac{1}{3}\pi r^2(h+2r)$

$=\frac{1}{3}\times \frac{22}{7}\times \left(3.5{)}^2\right(9+2\times 3.5)$

$=\frac{1}{3}\times \frac{22}{7}\times \left(3.5{)}^2\right(9+7)$

$=\frac{1}{2}\times \frac{22}{7}\times (3.5{)}^2\times 16$

$V$. of ice cream in the cone $=205.33c{m}^2$.