Question

An ice cube floats on water in a beaker with ${\frac{9}{10}}^{th}$ of its volume submerged under water. What fraction of its volume will be submerged if the beaker of water is taken to the moon where the gravity is $1/6^{th}$ that on the earth ?

• A. $\frac{9}{10}$
• B. $\frac{27}{50}$
• C. $\frac{2}{3}$
• D. Zero

Answer 1

The correct option is A $\frac{9}{10}$

Solution By Archimedes Principle,

Weight of floating object = weight of fluid displaced

$\Rightarrow$ mass of floating object = man of fluid

displaced

As the mass will remain same

in both moon and earth, the

fraction of volume submerged will

also remain same i.e, $\frac{9^{th}}{10}$

provided density of water is unaltered

Option - A is correct