An ice cube is kept on an inclined plane of angle 30o. Coefficient of kinetic friction between block and incline plane is 1/√3 What is acceleration of block.
Ice cube is kept on inclined plane of angle 30∘and kinetic friction is 1√3.
Now balancing forces
mgsin30−μkmg=ma
gsin30−μkg=a
a=(sin30−μk)g
a=(12−1√3)g
a=(√3−12√3)g
a=0.2113×9.8
a=2.07m/s2
a≈2m/s2
Thus acceleration of the block is 2m/s2.