An iceberg floats in sea water with 14% of its volume projecting above the sea surface. If the specific weight of sea water is 10400 $N / m^{3}$ , determine the specific weight of the iceberg in $N / m^{3}$ units

8944

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9125

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8836

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8314

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Solution

The correct option is A 8944

86% of iceberg is immersed in water i.e., volume of water displaced by iceberg is

$V_{w} = 0.86 V_{i}$

$W e i g h t o f i c e b e r g = W_{c} = γ_{i} V_{i}$

$W e i g h t o f s e a w a t e r d i s p l a c e d = γ_{w} \times V_{w}$

$= 10400 \times 0.86 V_{i}$

For equilibrium

Downward force = Upward force

$γ_{i} V_{i} = 10400 \times 0.86 \times V_{i}$

$∴ γ_{i} = 8944 N / m^{3}$

Suggest Corrections

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