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Question

An iceberg floats in sea water with 14% of its volume projecting above the sea surface. If the specific weight of sea water is 10400 N/m3, determine the specific weight of the iceberg in N/m3 units

A
8944
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B
9125
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C
8836
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D
8314
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Solution

The correct option is A 8944

86% of iceberg is immersed in water i.e., volume of water displaced by iceberg is

Vw=0.86Vi

Weight of iceberg=Wc=γiVi

Weight of sea water displaced=γw×Vw

=10400×0.86Vi

For equilibrium

Downward force = Upward force

γiVi=10400×0.86×Vi

γi=8944 N/m3

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