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Question

An iceberg is floating in sea water. The density of ice is 0.92gm/cm3 and that of sea water is 1.03gm/cm3. What percentage of the iceberg will be below the surface of water

A
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C
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Solution

The correct option is C
For the floatation of ice-berg, Weight of ice = upthrust due to displaced water
Vρg=Vinσg(ρσ)V=(0.921.03)V=0.89 V VinV=0.89 or 89%


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