An iceberg is floating in sea water. The density of ice is 0.92gm/cm3 and that of sea water is 1.03gm/cm3. What percentage of the iceberg will be below the surface of water
A
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B
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C
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D
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Solution
The correct option is C For the floatation of ice-berg,Weight of ice = upthrust due to displaced water Vρg=Vinσg⇒(ρσ)V=(0.921.03)V=0.89V∴VinV=0.89or89%