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Question

An ideal battery of 4V and resistance R are connected in series in the primary circuit of a potentiometer of length 1m and resistance 5Ω. The value of R, to given a potential difference of 5mVacross 10cm of potentiometer wire is:

A
490Ω
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B
480Ω
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C
395Ω
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D
495Ω
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Solution

The correct option is C 395Ω
Let current flowing in the wire is i.
i=(4R+5)A
If resistance of 10m length of wire is x
then x=0.5Ω=5×0.11Ω
ΔV=P.d on wire =i.x
5×103=(4R+5)(0.5)
4R+5=102
R=395Ω

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