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Question

An ideal diesel engine has a compression ratio of 20 and uses air as the working fluid. The state of air at the beginning of the compression process is 95 kPa and 20C . If the maximum temperature in the cycle is not to exceed 2200 K. (Take y for air = 1.4 and cp for air = 1.005 kJ/kgK) then the thermal efficiency is given by:

A
67.9%
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B
56.9%
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C
34.9%
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D
63.5%
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Solution

The correct option is D 63.5%


The properties of air at room temperature are

cp=1.005 kJ/kgK,cv=0.718 kJ/kgK,R=0.287 kJ/kgK and γ=1.4

T2=T1(V1V2)γ1=(293K)(20)0.4=971.1 K

Process 2-3: constant pressure heat addition,

P3V3Ts=P2V2T2V3V2=T3T2=2200K971.1K=2.265

Process 3-4: isentropic expansion,

T4=T3(V3V4)γ1=T3(2.265V2V4)γ1=Ts(2.265r)γ1

=(2200)(2.26520)0.4[V4=V1]

=920.6 K

qin=h3h1=cp(T3T2)=(1.005)(2200971.1)=1235.04kJ/kg

qout=u4u1=cv(T4T1)=(0.718)(920.6293)=450.6 kJ/kg

ωnet,out=qinqout=1235450.6=784.4kJ/kg

ηth=ωnet,outqin=784.4kJ/kg1235.04kJ/kg=63.5%


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