An ideal diesel engine has a compression ratio of 20 and uses air as the working fluid. The state of air at the beginning of the compression process is 95 kPa and 20∘C . If the maximum temperature in the cycle is not to exceed 2200 K. (Take y for air = 1.4 and cp for air = 1.005 kJ/kgK) then the thermal efficiency is given by:
The properties of air at room temperature are
cp=1.005 kJ/kgK,cv=0.718 kJ/kgK,R=0.287 kJ/kgK and γ=1.4
T2=T1(V1V2)γ−1=(293K)(20)0.4=971.1 K
Process 2-3: constant pressure heat addition,
P3V3Ts=P2V2T2⇒V3V2=T3T2=2200K971.1K=2.265
Process 3-4: isentropic expansion,
T4=T3(V3V4)γ−1=T3(2.265V2V4)γ−1=Ts(2.265r)γ−1
=(2200)(2.26520)0.4[∵V4=V1]
=920.6 K
qin=h3−h1=cp(T3−T2)=(1.005)(2200−971.1)=1235.04kJ/kg
qout=u4−u1=cv(T4−T1)=(0.718)(920.6−293)=450.6 kJ/kg
ωnet,out=qin−qout=1235−450.6=784.4kJ/kg
ηth=ωnet,outqin=784.4kJ/kg1235.04kJ/kg=63.5%