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Question

# An ideal fluid is flowing in a pipe in a streamline flow. The pipe has a maximum and minimum diameter of 6.4 cm and 4.8 cm respectively. Find out the ratio of minimum to maximum velocity.

A
81256
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B
916
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C
34
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D
316
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Solution

## The correct option is B 916Given: Maximum diameter of cylindrical pipe (d1)=6.4 cm Minimum diameter of cylindrical pipe (d2)=4.8 cm From equation of continuity, we can say that minimum velocity vmin is where Area A1 is maximum and maximum velocity vmax is where area A1 is minimum So, A1vmin=A2vmax ∴vminvmax=A2A1=πd22πd12=(4.86.4)2=916

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