You visited us 1 times! Enjoying our articles? Unlock Full Access!

Bernoulli's Principle

An ideal flui...

Question

An ideal fluid is flowing through the given tubes which is placed on a horizontal surface. If the liquid has velocities $v_{A}$ and $v_{B}$ , and pressures $P_{A}$ and $P_{B}$ at points $A$ and $B$ respectively, then the correct relation is:
(The figure shown below is as if the system is seen from the top)

v_{A} > v_{B}, P_{A} < P_{B}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

v_{A} < v_{B}, P_{A} > P_{B}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

v_{A} = v_{B}, P_{A} = P_{B}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

v_{A} > v_{B}, P_{A} = P_{B}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $v_{A} = v_{B}, P_{A} = P_{B}$
Applying continuity equation:
$v_{A} A_{A} = v_{B} A_{B}$
$A_{A} = A_{B}$ , so $v_{B} = v_{A}$
Applying Bernoulli's equation:
$P_{A} + ρ g h_{A} + \frac{1}{2} ρ v_{A}^{2} = P_{B} + ρ g h_{B} + \frac{1}{2} ρ v_{B}^{2}$
Since $v_{A} = v_{B}$ , and pipes are placed on a horizontal surface $(h_{A} = h_{B})$
$\Rightarrow P_{A} = P_{B}$

Suggest Corrections

Similar questions

v_{A}

v_{B}

P_{A}

P_{B}

A

B

v_{A}

v_{B}

P_{A}

P_{B}

v_{A}

v_{B}

P_{A}

P_{B}

A

B

A

B

2 m m^{2}

4 m m^{2}

A

4 m / s

B

Water is flowing through a long horizontal tube. Let P_A and P_B be the pressures at two points A and B of the tube.

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program