An ideal gas at 27oC is compressed adiabatically and reversibly to 827 of its original volume. If γ=53, then the rise in temperature is
A
450K
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
375K
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
225K
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
405K
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B375K For an adiabatic process T2T1=(V1V2)γ−1 where, T1= initial temperature T2= final temperature V1= initial volume V2= final volume =827V1 γ=53 ⇒T2=300(278)53−1=300(278)23 =300(32)2=300(94)=675K therefore rise in tempearture is : ⇒△T=675−300=375K