An ideal gas at 27oC is compressed adiabatically to 827 of its original volume. The rise in temperature is (Take γ=5/3)
A
475K
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B
150K
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C
275K
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D
375K
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Solution
The correct option is D375K In an adiabatic process, TVγ−1=constant T1T2=(V2V1)γ−1 300T2=⎛⎜
⎜
⎜⎝827VV⎞⎟
⎟
⎟⎠53−1=(827)23=49 T2=300×94=675K ∴Rise in temperature=675−300=375K Option D.