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Question

An ideal gas (Cv=32R) is maintained in a vessel of volume 83×104m3 at pressure 1.6×106Nm2 and temperature 300K. If 2.49×104 J heat is given to this vessel, then its final temperature will be

A
600K
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B
625K
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C
650K
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D
675K
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Solution

The correct option is D 675K
Q=nCvdT2.49×104=PVRT×(Cv)×(T2T1)

2.49×104=83×104×1.6×1068.314×300×(1.5×8.314) (T2300)

T2300=375T2=675K

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