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Question

An ideal gas goes from state A to state B via three different processes as indicated in the P-V diagram-
If Q1,Q2,Q3 indicate the heat absorbed by the gas along the three processes and ΔU1,ΔU2,ΔU3 indicate the change in internal energy along the three processes respectively, then-
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A
Q3>Q2>Q1 and ΔU1=ΔU2=ΔU3
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B
Q1=Q2=Q3 and ΔU1>ΔU2>ΔU3
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C
Q3>Q2>Q1 and ΔU1>ΔU2>ΔU3
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D
Q1>Q2>Q3 and ΔU1=ΔU2=ΔU3
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Solution

The correct option is B Q1>Q2>Q3 and ΔU1=ΔU2=ΔU3
dU1=dU2=dU3
Q1>Q2>Q3
Because
ΔQ=ΔW+dU
Change in internal energy independent of path and work depends on path and the heat required increases as the work done increases.
ΔQ1>ΔQ2>ΔQ3

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