An ideal gas has a volume of $10$ L at $20^{o} C$ and $750$ mmHg. Which of the following expressions is needed to determine the volume of the same amount of gas at STP?

10 \times \frac{750}{760} \times \frac{1}{20}

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10 \times \frac{750}{760} \times \frac{293}{273}

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10 \times \frac{760}{750} \times \frac{293}{273}

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10 \times \frac{760}{750} \times \frac{273}{293}

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10 \times \frac{750}{760} \times \frac{273}{293}

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Solution

The correct option is C $10 \times \frac{750}{760} \times \frac{293}{273}$ L
For constant no. of moles, $\frac{P_{1} V_{1}}{T_{1}}$ $=$ $\frac{P_{2} V_{2}}{T_{2}}$

At $S T P$ , temperature $T_{2}$ $=$ $273 K$ and $P_{2}$ $=$ $760$ mmHg

So, volume at $S T P$ , $V_{2}$ $=$ $\frac{P_{1} V_{1} T_{2}}{P_{2} T_{1}}$ or $V_{2}$ $=$ $10 \times \frac{293}{273} \times$ $\frac{750}{760}$ L

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Similar questions

20^{o} C

m m

H g

S T P

273^{\circ}

1.12 \times 10^{- 7} c c

2 L

S O_{2}

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(G i v e n R = 0.082 L atm K^{- 1} {mol}^{- 1}, 760 torr = 1 atm, 0^{\circ} C = 273 K)

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