wiz-icon
MyQuestionIcon
MyQuestionIcon
14
You visited us 14 times! Enjoying our articles? Unlock Full Access!
Question

An ideal gas having initial pressure P volume V and temperature T is allowed to expand adiabatically until its volume becomes 5.66V, while its temperature falls to T/2. Find the number of degrees of freedom of the gas molecule.
(Take (5.66)0.4=2)

A
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
5
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 5
For an adiabatic process,
TVγ1 = constant
i.e. T1Vγ11=T2Vγ12
TVγ1=T2(5.66V)γ1
(5.66)γ1=2
γ=1.4
We know that, γ=1+2f
we get f=2γ1=20.4=5

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Theory of Equipartitions of Energy
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon