Question

An ideal gas heat engine operates between ${227}^{o}C$ and ${127}^{o}C$, it absorbs 6 x ${10}^4$ cal at the higher temperature, the amount of heat converted into work is equal to

• A. $4.8\times {10}^{4}cal$
• B. $3.5\times {10}^{4}cal$
• C. $1.6\times {10}^{4}cal$
• D. $1.2\times {10}^{4}cal$

Answer 1

The correct option is D $1.2\times {10}^{4}cal$

Efficiency of a Carnot engine is
$\eta =\frac{W}{Q_h}=1-\frac{T_c}{T_h}$
$\frac{W}{6\times {10}^4}=1-\frac{400}{500}=\frac{1}{5}$
$W=1.2\times {10}^{4}cal$
Option D.