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Question

An ideal gas initially at 30K undergoes an isobaric expansion at 2.50 kPa. If the volume increases from 1.00 m3 to 3.00 m3 and 12.5 kJ is transferred to the gas by heat, What is the change in its internal energy?

A
7500 J
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B
7000 J
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C
700 J
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D
750 J
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Solution

The correct option is A 7500 J
in an isobaric process, pressure remains constant
According to first Law of thermodynamics :
ΔQ=ΔU+ΔW
ΔQ=ΔU+PΔV P = constant
ΔU=ΔQPΔV
ΔQ=12.5 kJ, ΔV=(31)m3, P=2.5 kPa
so ΔU=12500J2×2500J
ΔU=7500J

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