An ideal gas is allowed to expand from $1 L$ to $10 L$ against a constant external pressure of $1 bar$ . The work done in $k J$ is:

- 9.0

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+ 10.0

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- 0.9

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- 2.0

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Solution

The correct option is C $- 0.9$
According to the given conditions, the expansion is against constant external pressure. So, the work done is given by following formula;
$W = - p_{e x t} (V_{2} - V_{1})$
$= - 1 bar (10 L - 1 L)$
$= - 9 L bar$
$= - 9 \times 100 J = - 0.9 kJ$

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An ideal gas is allowed to expand from 1 L to 10 L against a constant external pressure of 1 bar. The work done in kJ is:

The correct option is C −0.9According to the given conditions, the expansion is against constant external pressure. So, the work done is given by following formula; W=−pext(V2−V1) =−1 bar(10 L−1 L) =−9 L bar =−9×100 J=−0.9 kJ

An ideal gas is allowed to expand from $1 L$ to $10 L$ against a constant external pressure of $1 bar$ . The work done in $k J$ is:

The correct option is C $- 0.9$
According to the given conditions, the expansion is against constant external pressure. So, the work done is given by following formula;
$W = - p_{e x t} (V_{2} - V_{1})$
$= - 1 bar (10 L - 1 L)$
$= - 9 L bar$
$= - 9 \times 100 J = - 0.9 kJ$