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An ideal gas ...

Question

An ideal gas is allowed to expand from $1 L$ to $10 L$ against a constant external pressure of $1$ bar. The magnitude of work done in $J$ is:

A

900.00

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B

900.0

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C

0.9

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D

900

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Solution

$W = - P_{e x t} (V_{2} - V_{1}) = - 1 b a r \times (10 - 1) L = - 9 b a r . L = - 900 J$
Magnitude of work done = $900 J$

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