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Question

An ideal gas is enclosed in a cylinder with a movable piston on top of it. The piston has a mass of 8000 g and an area of 5.00 cm2 and is free to slide up and down, keeping the pressure of the gas constant. How much work in Joules is done on the gas as the temperature of 0.200 mol of the gas is raised from 20.0oC to 300oC?

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Solution

First law of thermodynamics gives us the relation.
q=ΔU+w
w=qΔU
For a constant pressure process,
q=nCpΔT
ΔU=nCvΔT (always)
Hence, w=n(CpCv)ΔT=nRΔT=0.2×8.314×(30020)=466J

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