An ideal gas is expanding such that $P T^{2} = c o n s t a n t$ . The coefficient of volume expansion of the gas is

\frac{1}{T}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{2}{T}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{3}{T}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{4}{T}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\frac{3}{T}$
From $P V = n R T$ , we can replace P proportional to T/V and have $V T^{- 3}$ = constant. differentiating, we get $\frac{d V}{V d T} = \frac{3}{T}$

Suggest Corrections

Similar questions

P T^{2} = c o n s t a n t

P T^{2} = constant

P T =

P T^{2} =

P T^{2} = c o n s t a n t

Join BYJU'S Learning Program