An ideal gas is filled in compartment A of a container shown below
A
5 mole
5litre B
5 litre
Compartment B is empty and volume of both A and B is $5$ litre each. Partition between A and B compartments is removed suddenly. If pressure of gas in A was initially $4$ atm then work done by gas during expansion is -(Assuming no heat exchange with surroundings)

10

atm -L

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40

atm -L

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20

atm -L

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Solution

The correct option is D $20$ atm -L
Given, $P = 4 a t m$
$V_{2} = 10 L$
$V_{1} = 5 L$

Work done= $P Δ V$
$= 4 a t m \times (10 - 5) L$
$= 4 \times 5$
$= 20 a t m L$

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