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Question

An ideal gas is initially at a temperature T and volume V. Its volume is increased by ΔV due to an increase in temperature ΔT, pressure remaining constant. The quantity δ=ΔV/(VΔT) varies with temperature as

A
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B
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C
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D
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Solution

The correct option is C
From ideal gas equation
PV=nRT (1)PΔV=nRΔT (2)

Dividing equation (2) by equation (1), we get

ΔVV=ΔTTΔVVΔT=1T=δ

δ=1T

So the graph between δ and T will be a rectangular hyperbola.

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