An ideal gas is initially at temperature T and volume V and at constant pressure, its volume increases by ΔV due to an increase in temperature by ΔT. The quantity μ=ΔV/VΔT varies with temperature as:
A
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B
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C
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D
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Solution
The correct option is D According to Charle's Law: V=KT ⇒ΔV=KΔT ⇒ΔVΔT=K...(i) ⇒μ=ΔVVΔT ⇒μ∝1V
According to Charle's Law: V∝T
So, μ∝1T
So, graph between μ and T will be a rectangular hyperbola.