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Question

An ideal gas is initially at temperature T and volume V and at constant pressure, its volume increases by ΔV due to an increase in temperature by ΔT. The quantity μ=ΔV/VΔT varies with temperature as:

A
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B
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C
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D
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Solution

The correct option is D
According to Charle's Law: V=KT
ΔV=KΔT
ΔVΔT=K ...(i)
μ=ΔVVΔT
μ1V
According to Charle's Law: VT
So, μ1T
So, graph between μ and T will be a rectangular hyperbola.

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