Question

An ideal gas is kept inside a $4\text{L}$ container at a temperature of $300\text{K}$ and a pressure of $6\text{atmospheres}$. If the pressure is held constant while the volume of the gas is doubled, then find out the new temperature of the gas.

• A. $1200\text{K}$
• B. $600\text{K}$
• C. $300\text{K}$
• D. $150\text{K}$

Answer 1

The correct option is B $600\text{K}$

Here, pressure is kept constant,
So, by using Charle's law at constant pressure, we can say that,
$V\propto T$
or $\frac{T_2}{T_1}=\frac{V_2}{V_1}..\left(1\right)$
Given,
$T_1=300\text{K},V_1=4\text{L},V_2=2\times 4=8\text{L}$
$\therefore$ we can write from $\left(1\right)$ that,
$\frac{T_2}{300}=\frac{8}{4}$
or $T_2=300\times \frac{8}{4}=600\text{K}$
Thus, option (b) is the correct answer.