An ideal gas is taken around ABCA as shown in the above P-V diagram. The work done during a cycle is

2PV

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1/2PV

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Zero

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Solution

The correct option is A 2PV
Work done = Area enclosed by triangle ABC $= \frac{1}{2} A C \times B C = \frac{1}{2} \times (3 V - V) \times (3 P - P) = 2 P V$

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An ideal gas is taken through a cycle ABCA as shown in P – V diagram. The work done during the cycle is

A B C A

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