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Heat Engines

An ideal gas ...

Question

An ideal gas is taken through a cyclic thermodynamic process through four steps. The amounts of heat involved in these steps are $Q_{1} = 5960$ J, $Q_{2} = - 5585$ J, $Q_{3} = - 2980$ J and $Q_{4} = 3645$ J respectively. The corresponding works involved are $W_{1} = 2200$ J, $W_{2} = - 825$ J, $W_{3} = - 1100$ J and $W_{4}$ respectively. Find the value of $W_{4}$ .

A

3670 J

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B

1880 J

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C

4760 J

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D

765 J

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Solution

The correct option is D $765 J$
From first law of thermodynamics,
$Δ U = Δ Q + Δ W$
For cyclic process,total internal energy will be 0 so
$W_{4} = 765$

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Q. An ideal gas is taken through a cyclic thermodynamic process through four steps. The amounts of heat involved in these steps are:

Q_{1} = 5960

Q_{2} = 5585

Q_{3} = 2980

Q_{4} = 3645

J ; respectively, The corresponding works involved are

W_{1} = 2200

W_{2} = 825

W_{3} = 1100

W_{4}

respectively. The value of

W_{4}

Q. An ideal gas is taken through a cyclic thermodynamic process through four steps

1, 2, 3, 4

respectively. The amounts of heat involved in these steps are

Q_{1} = 5960 J, Q_{2} = 5585 J, Q_{3} = - 2980 J

Q_{4} = 3645 J

respectively. The corresponding quantities of work involved are

W_{1} = 2200 J, W_{2} = 8250 J, W_{3} = - 1100 J

W_{4}

respectively. The value of

W_{4}

Q. An ideal gas is taken through a cyclic thermodynamic process through four steps. The amounts of heat involved in these steps are

Q_{1} = 5960 J

Q_{2} = - 5585 J

Q_{3} = - 2980 J

Q_{4} = 3645 J

respectively. The corresponding quantities of work involved are

W_{1} = 2200 J

W_{2} = - 825 J, W_{3} = - 1100 J

W_{4}

respectively . Find the efficiency of the cycle.

Q. An ideal gas is taken through a cyclic thermodynamic process through four steps. The amounts of heat involved in these steps are

Q_{1} = 5960 J, Q = - 5585 J, Q_{3} = - 2980 J

Q_{4} = 3645 J

respectively. The corresponding quantities of work done by gas for each steps are

W_{1} = 2200 J, W_{2} = - 825 J, W_{3} = - 1100 J

W_{4} = 765 J

respectively. The efficiency of the cycle is

Q. An ideal gas is taken through a cyclic thermodynamic process through four steps. The amounts of heat involved in these steps are

Q_{1} = 5960 J

Q_{2} = - 5585 J

Q_{3} = - 2980 J

Q_{4} = 3645 J

respectively. The corresponding works involved are

W_{1} = 2200 J

W_{2} = - 825 J

W_{3} = - 1100 J

W_{4}

respectively.
What is the efficiency of the cycle?

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