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1st Law of Thermodynamics

An ideal gas ...

Question

An ideal gas is taken through a cyclic thermodynamic process through four steps. The amounts of heat involved in these steps are: $Q_{1} = 5960$ J, $Q_{2} = 5585$ J, $Q_{3} = 2980$ J, $Q_{4} = 3645$ J ; respectively, The corresponding works involved are $W_{1} = 2200$ J, $W_{2} = 825$ J, $W_{3} = 1100$ J and $W_{4}$ respectively. The value of $W_{4}$ is

A

12315 J

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B

12275 J

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C

14045 J

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D

14675 J

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Solution

The correct option is B 14045 J
For a cyclic process,

Total amount of heat energy involved $=$ Total amount of work done

$Q_{1} + Q_{2} + Q_{3} + Q_{4} = W_{1} + W_{2} + W_{3} + W_{4}$

$5960 + 5585 + 2980 + 3645 = 2200 + 825 + 1100 + W_{4}$

$W_{4} = 14045 J$

Hence, option C is correct.

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Similar questions

Q. An ideal gas is taken through a cyclic thermodynamic process through four steps. The amounts of heat involved in these steps are

Q_{1} = 5960

Q_{2} = - 5585

Q_{3} = - 2980

Q_{4} = 3645

J respectively. The corresponding works involved are

W_{1} = 2200

W_{2} = - 825

W_{3} = - 1100

W_{4}

respectively. Find the value of

W_{4}

.

Q. An ideal gas is taken through a cyclic thermodynamic process through four steps. The amounts of heat involved in these steps are

Q_{1} = 5960 J

Q_{2} = - 5585 J

Q_{3} = - 2980 J

Q_{4} = 3645 J

respectively. The corresponding quantities of work involved are

W_{1} = 2200 J

W_{2} = - 825 J, W_{3} = - 1100 J

W_{4}

respectively . Find the efficiency of the cycle.

Q. An ideal gas is taken through a cyclic thermodynamic process through four steps

1, 2, 3, 4

respectively. The amounts of heat involved in these steps are

Q_{1} = 5960 J, Q_{2} = 5585 J, Q_{3} = - 2980 J

Q_{4} = 3645 J

respectively. The corresponding quantities of work involved are

W_{1} = 2200 J, W_{2} = 8250 J, W_{3} = - 1100 J

W_{4}

respectively. The value of

W_{4}

Q. An ideal gas is taken through a cyclic thermodynamic process through four steps. The amounts of heat involved in these steps are

Q_{1} = 5960 J, Q = - 5585 J, Q_{3} = - 2980 J

Q_{4} = 3645 J

respectively. The corresponding quantities of work done by gas for each steps are

W_{1} = 2200 J, W_{2} = - 825 J, W_{3} = - 1100 J

W_{4} = 765 J

respectively. The efficiency of the cycle is

Q. An ideal gas is taken through a cyclic thermodynamic process through four steps. The amounts of heat involved in these steps are

Q_{1} = 5960 J

Q_{2} = - 5585 J

Q_{3} = - 2980 J

Q_{4} = 3645 J

respectively. The corresponding works involved are

W_{1} = 2200 J

W_{2} = - 825 J

W_{3} = - 1100 J

W_{4}

respectively.
What is the efficiency of the cycle?

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