Question

An ideal gas of mass m in a state A goes to another state B via three different process as shown in fig. If $Q_1$, $Q_2$, and $Q_3$ denote the heat absorbed by the gas along the three paths, then

• A. $Q_1$ < $Q_2$ < $Q_3$
• B. $Q_1$ = $Q_2$ = $Q_3$
• C. $Q_1$ = $Q_2$ > $Q_3$
• D. $Q_1$ > $Q_1$ > $Q_1$

Answer 1

The correct option is A $Q_1$ < $Q_2$ < $Q_3$

from the first law of thermodynamics $Q=U+W$

here internal energy will be same for all the path,hence the required equation will be $Q=W$

now the path which have higher work done will also have higher heat .

so, $W_1<W_2<W_3$

also,$Q_1<Q_2<Q_3$