An ideal gas undergoes a circular cycle centered at 4atm, 4 lit as shown in the diagram. The maximum temperature attained in this process is close to.

30/R

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36/R

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24/R

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16/R

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Solution

The correct option is A 30/R
For one mole $T = \frac{P V}{R}$
$T = \frac{(4 + 2 s i n θ) (4 + 2 c o s θ)}{R}$
Since $s i n θ a n d c o s θ$ cannot be one at same time So , $T_{m a x} < \frac{36}{R}$
Isothermal temperature $T_{i s o} = \frac{24}{R}$
So possible value will be between $\frac{24}{R} < T < \frac{36}{6}$
option 1 correct

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An ideal gas undergoes a circular cycle centered at 4atm, 4 lit as shown in the diagram. The maximum temperature attained in this process is close to.

The correct option is A 30/RFor one mole T=PVRT=(4+2sinθ)(4+2cosθ)RSince sinθandcosθ cannot be one at same time So ,Tmax<36RIsothermal temperature Tiso=24R So possible value will be between 24R<T<366option 1 correct