An ideal gas undergoes a cyclic process as shown in Figure- - UBC-5 kJ mol-1- qAB-2 kJ mol-1 WAB-5 kJ mol-1- WCA-3 kJ mol-1Heat absorbed by the system during process CA is-

The correct option is D +5 kJ mol^ 1 Δ U _AB = q_AB+W_AB=2+( 5)= 3 kJ/mol Δ U _BC = #160; 5 kJ/mol For cyclic process, Δ U = 0 ...

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Heat Capacity

An ideal gas ...

Question

An ideal gas undergoes a cyclic process as shown in Figure.
$Δ U_{B C} = - 5$ kJ $m o l^{- 1}$ , $q_{A B} = 2$ kJ $m o l^{- 1}$
$W_{A B} = - 5$ kJ $m o l^{- 1}$ , $W_{C A} = 3$ kJ $m o l^{- 1}$
Heat absorbed by the system during process CA is:

+ 18

m o l^{- 1}

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- 18

m o l^{- 1}

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- 5

m o l^{- 1}

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+ 5

m o l^{- 1}

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Solution

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Similar questions

k J m o l^{- 1},

38 k J m o l^{- 1}

H = 218 k J m o l^{- 1}, C = 715 k J m o l^{- 1}, O = 249 k J m o l^{- 1}

C - H = 415 k J m o l^{- 1} C - O = 356 k J m o l^{- 1} O - H = 463 k J m o l^{- 1}

C a C l_{2}

C a (s) \to C a (g) = 121 k J m o l^{- 1}

C l_{2} (g) \to 2 C l (g) = 242.8 k J m o l^{- 1}

C a (g) \to C a^{+ +} (g) = 2422 k J m o l^{- 1}

2 C l \to 2 C l^{- 1} = (2 \times - 355) k J m o l^{- 1} = - 710 k J m o l^{- 1}

C a C l_{2} = - 795 k J m o l^{- 1}

1 m o l

C l_{2}

d m^{3}

d m^{3}

273 K

l o g 5 = 0.693

N_{2} O

△_{f} H^{o} o f N_{2} O = 82 k J m o l^{- 1},

N \equiv N, 946 k J m o l^{- 1}; N = N, 418 k J m o l^{- 1};

O = O, 498 k J m o l^{- 1}; N = O, 607 k J m o l^{- 1}

N a^{+}

- 389.4 {kJ mol}^{- 1}

C l^{-}

- 382.3 {kJ mol}^{- 1}

N a C l = + 776 {kJ mol}^{- 1}

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