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Question

An ideal gas undergoes a cyclic process as shown in Figure.

ΔUBC=5 kJ mol1, qAB=2 kJ mol1
WAB=5 kJ mol1, WCA=3 kJ mol1
Heat absorbed by the system during process CA is:

868120_af609f5cc16d4673804cea4f5bff0cf1.png

A
+18 kJ mol1
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B
18 kJ mol1
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C
5 kJ mol1
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D
+5 kJ mol1
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Solution

The correct option is D +5 kJ mol1
ΔUAB=qAB+WAB=2+(5)=3kJ/mol
ΔUBC=5kJ/mol
For cyclic process, ΔU=0
ΔUAB+ΔUBC+ΔUCA=0
ΔUCA=ΔUABΔUBC
ΔUCA=(3)(5)=8kJ/mol
ΔUCA=qCA+WCA
8=qCA+3
qCA=+5kJ/mol
Heat absorbed has positive sign.

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