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Question

An ideal gas undergoes a process in which PVa = constant, where V is the volume occupied by the gas initially at pressure P. At the end of the process, rms speed of gas molecules has become a12 times of its initial value. The value of CV so that energy transferred by the heat to the gas becomes 'a' times of the initial energy is
R((1+a)a1naa21]. The value of n is

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Solution

PVa= constant
Molar heat capacity in the process is given by
C=CV+R1x (for PVx= constant)
=CV+R1(a)
=CV+R1+a
At the end of the process Vrms is a12 times initial value
temperature is 'a' times intial value (VrmsT12)
ΔQ=nCΔT=nCT(a1)
=nT(a1)[CV+R1+a]
But it is given that ΔQ=aPV
aPVnRT(a1)a+1=n(a1)CVT
aPV(a1)a+1PV=n(a1)CVT
(PV=nRT)
(a2+1)PV=n(a21)CVT
CV=PV(a2+1)nT(a21)=R(a2+1)(a21)

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