CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

An ideal gas undergoes a process in which PVa = constant, where V is the volume occupied by the gas initially at pressure P. At the end of the process, rms speed of gas molecules has become a12 times of its initial value. The value of CV so that energy transferred by the heat to the gas becomes 'a' times of the initial energy is
R((1+a)a1naa21]. The value of n is

Open in App
Solution

PVa= constant
Molar heat capacity in the process is given by
C=CV+R1x (for PVx= constant)
=CV+R1(a)
=CV+R1+a
At the end of the process Vrms is a12 times initial value
temperature is 'a' times intial value (VrmsT12)
ΔQ=nCΔT=nCT(a1)
=nT(a1)[CV+R1+a]
But it is given that ΔQ=aPV
aPVnRT(a1)a+1=n(a1)CVT
aPV(a1)a+1PV=n(a1)CVT
(PV=nRT)
(a2+1)PV=n(a21)CVT
CV=PV(a2+1)nT(a21)=R(a2+1)(a21)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Equations Redefined
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon