Question

An ideal gas undergoes a process such that $dW=0$ and $dQ>0$. Then which of the following is correct?

• A. The temperature of the gas will decrease.
• B. The volume of the gas will increase.
• C. The pressure of the gas will remain constant.
• D. The temperature of the gas will increase.

Answer 1

The correct option is D The temperature of the gas will increase.

From first law,
$dQ=dU+dW$
As, $dW=0$
$\Rightarrow$ $dQ=dU$
If $dQ>0$ this means $dU$ is also positive means internal energy is increased, which means temperature will increase.