An ideal gas undergoes adiabatic expansion against external pressure. Which of the following are correct ?

Internal energy of the gas remains unchanged

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Internal energy of the gas decrease

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Temperature of the system decreases

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Δ E + P Δ V = 0

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Solution

The correct options are
B Internal energy of the gas decrease
C Temperature of the system decreases
D $Δ E + P Δ V = 0$
For adiabatic process, q = 0.
Hence $Δ E = W = - P Δ V$
Also, $Δ E = C_{v} Δ T = - P Δ V$
Since $Δ V$ is positive for expansion, $Δ E$ will be negative and so also $Δ T$

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