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Question

An ideal gas undergoes an expansion from a state with temperature T1 and volume V1 through three different polytropic process A, B and C as shown in the PV diagram. If |ΔEA|,|ΔEB| and |ΔEC| be the magnitude of changes in internal energy along the three paths respectively, then


A
|ΔEA|<|ΔEB|<|ΔEC| if temperature in every process decreases
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B
|ΔEA|>|ΔEB|>|ΔEC| if temperature in every process decreases
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C
|ΔEA|>|ΔEB|>|ΔEC| if temperature in every process increases
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D
|ΔEB|<|ΔEA|<|ΔEC| if temperature in every process increases
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Solution

The correct option is C |ΔEA|>|ΔEB|>|ΔEC| if temperature in every process increases
Initial state is same for all the three processes (say initial internal energy =E0).
In the final state, VA=VB=VC
and PA>PB>PC
PAVA>PBVB>PCVC
EA>EB>EC
If temperature in every process decreases, i.e. T1>Tf, then E0>Ef for all the three process and hence (E0EA)<(E0EB)<(E0EC)
|ΔEA|<|ΔEB|<|ΔEC|
If temperature in every process increases, i.e. T1<T2, then E0<Ef for all the three process and hence (EAE0)>(EBE0)>(ECE0)
|ΔEA|>|ΔEB|>|ΔEC|
Why this Question ?

Key Concept: Conservation of energy using first law of thermodynamics.

Importance for JEE: Graphical analysis of work done in relation with Internal energy is important in JEE

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