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Question

An ideal gas undergoing cyclic process ABCA is shown in the PT diagram. Which of the following curves correctly represents the process on a VT diagram?


A
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B
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C
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D
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Solution

The correct option is B
Process AB on PT curve:
PT= constant
Volume constant (as, PV=nRT)
On, VT curve, it will be a horizontal line left to right.

Process BC on PT curve:
Temperature constant it is isothermal process.
PV=constantP1V
On VT curve it will be a vertical line with increasing volume.

Process CA on PT curve:
Pressure constant it is isobaric process with decreasing temperature
TV
(From ideal gas equation PV=nRT.
When P = constant)
On VT curve it will be inclined downwards.
Only option (b), matches all the conclusions.

Why this question?One should know how to interpret andand analyze property diagram.

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