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Byju's Answer
Standard XII
Chemistry
Work done in Isothermal Irreversible Process
An ideal gas ...
Question
An ideal gas undergoing expansion in vaccum shows
1) deltaE= 0
2) W=0
3 q=0
Why? Give explaination.
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Solution
Dear Student,
For
free
expansion
of
ideal
gas
=
external
pressure
=
0
W
=
-
P
∆
V
=
0
Isothermal
means
∆
T
=
0
and
∆
E
=
0
∆
H
=
∆
E
+
P
∆
V
Since
its
a
free
expansion
,
P
∆
V
=
0
∆
H
=
0
Otherwise
P
∆
V
=
R
∆
(
Tn
)
=
R
(
∆
T
)
(
∆
n
)
=
0
So
∆
H
=
0
Suggest Corrections
0
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