The correct option is A (A)→(S);(B)→(R);(C)→(Q);(D)→(P)
Given,
γ=75,P=2V,Vo=1 unit
and Vf=4V0
Work done in an adiabatic process W=∫VfViPdV
W=∫4V0V02VdV=[V2]4V0V0=15V20=15 units
Hence, (A)→(S).
Increment in internal energy
Ideal gas equation : PV=nRT,
where, P=2V
so, 2V2=nRT2(V2f−V20)=nR(ΔT)2(42−12)V20=nR(ΔT)⇒nRΔT=30V20 ....(1)
Internal energy in an adiabatic process is given by
ΔU=nCvΔT=nRγ−1ΔT
using eq. (1),
30V20γ−1=30(1)275−1=302(5)=75 units
Hence, (B)→(R).
Calculation of heat supply,
Q=W+ΔU
As we have calculated early,
W=15 unit
and ΔU=75 unit
Q=15+75=90 units
Hence, Hence, (C)→(Q).
Molar heat capacity for PVx process is given as:
C=Cv+R1−x=52R+R1−(−1)=52R+R2=3R=3×253=25 units
Hence, Hence, (D)→(P).