An ideal gaseous mixture of ethane (C2H6) and ethene (C2H4) occupies 28 litre at 1 atm and 273 K. The mixture reacts completely with 128 gm O2 to produce CO2 and H2O. Mole fraction at C2H4 in the mixture is:
A
0.6
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B
0.4
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C
0.5
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D
0.8
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Solution
The correct option is D 0.4 C2H6+3.5O2→2CO2+3H2O C2H4+3O2→2CO2+2H2O Let vol. of ethane is x, 22.4×4=3.5x+3(28−x) ⇒x=11.2 litre at constant T and P , V∝n; ∴ Mole fraction of C2H6 in mixture =11.228=0.4