An ideal heat engine is working between temperature T1 and T2 has efficiency - - If both the temperatures are raised by 100oK each- the new efficiency will be

The correct option is B less than η The efficiency of a system is defined as, η = T_2 T_1T_2 Now, if both the temperatures are increased, #160; ...

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Standard XII

Chemistry

Internal Energy

An ideal heat...

Question

An ideal heat engine is working between temperature $T_{1}$ and $T_{2}$ has efficiency $η$ . If both the temperatures are raised by $100^{o} K$ each, the new efficiency will be

η

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less than

η

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more than

η

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cannot be perdicted

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Solution

The correct option is B less than $η$
The efficiency of a system is defined as,
$η = \frac{T_{2} - T_{1}}{T_{2}}$
Now, if both the temperatures are increased,
$η^{'} = \frac{T_{2} - T_{1}}{T_{2} + 100}$
Thus, $η^{'} < η$

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An ideal heat engine is working between temperature T1 and T2 has efficiency η . If both the temperatures are raised by 100oK each, the new efficiency will be

The correct option is B less than ηThe efficiency of a system is defined as,η=T2−T1T2Now, if both the temperatures are increased, η′=T2−T1T2+100Thus, η′<η

An ideal heat engine is working between temperature $T_{1}$ and $T_{2}$ has efficiency $η$ . If both the temperatures are raised by $100^{o} K$ each, the new efficiency will be

The correct option is B less than $η$
The efficiency of a system is defined as,
$η = \frac{T_{2} - T_{1}}{T_{2}}$
Now, if both the temperatures are increased,
$η^{'} = \frac{T_{2} - T_{1}}{T_{2} + 100}$
Thus, $η^{'} < η$