An ideal heat engine receives heat from a source at 1250 K at a rate of 450 kW and rejects heat to a medium at 33-C - The power output of the engine is 195 kW- The irreversibility rate associated is

nbsp;η _Carnot= η _rev = 1 T_LT_H = W_revQ_s W_rev = ( 1 (33+273)1250 )× 450 = 339.84 kW Irreversibility rate nbsp;I= W_rev W_actual I= 339.84 195 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Heat Capacity

An ideal heat...

Question

An ideal heat engine receives heat from a source at 1250 K at a rate of 450 kW and rejects heat to a medium at $33^{\circ} C$ . The power output of the engine is 195 kW. The irreversibility rate associated is

144.84 kW

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

195 kW

No worries! We‘ve got your back. Try BYJU‘S free classes today!

228.21 kW

No worries! We‘ve got your back. Try BYJU‘S free classes today!

450 kW

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 144.84 kW
$η_{C a r n o t} = η_{r e v} = 1 - \frac{T_{L}}{T_{H}} = \frac{W_{r e v}}{Q_{s}}$

$W_{r e v} = (1 - \frac{(33 + 273)}{1250}) \times 450 = 339.84 k W$

$Irreversibility rate I = W_{r e v} - W_{a c t u a l}$

$I = 339.84 - 195 = 144.84 k W$

Suggest Corrections

Similar questions

Q. An irreversible heat engine extracts heat from a high temperature source at a rate of

100 k W

and rejects heat to a sink at a rate of

50 k W

. The entire work output of the heat engiine is used to drive a reversibel heat pump operating between as set of independent isothermal heat reservoirs at

17^{o} C

and

75^{o} C

. The rate (in

k W

) at which the heat pump delivers heat to its hight temperature sink is

Q. An irreversible heat engine operates between

47^{\circ} C and 637^{\circ} C .

The rate of heat rejection per 2 kW of net output can be

Q. In a cyclic heat engine operating between a source temperature of

600^{0} C

and a sink temperature of

20^{0} C

, the least rate of heat rejection per kW net output of the engine is,

Q. A Carnot heat engine absorbs heat from three thermal reservoirs at 1000 K, 800 K and 600 K. The engine develops 10 kW of power and rejects 6.67 kW of heat to a sink at 300 K. If the heat supplied by reservoir at 1000 K is 60% of the heat supplied by a resevoir at 600 K, then the heat supplied by the reservoir at 800 K is closest to

Q. A solar collector receiving solar radiation at the rate of

0.6 {kWm}^{- 2}

transforms it into the internal energy of a fluid at an overall efficiency of

50 %

. The fluid heated to

350 K

is used to run a heat engine which rejects heat at

313 K

. If the heat engine is to deliver

2.5 kW

power, the minimum area of the solar collector required would be

Join BYJU'S Learning Program

An ideal heat engine receives heat from a source at 1250 K at a rate of 450 kW and rejects heat to a medium at 33∘C . The power output of the engine is 195 kW. The irreversibility rate associated is

The correct option is A 144.84 kW ηCarnot=ηrev=1−TLTH=WrevQs Wrev=(1−(33+273)1250)×450=339.84 kW Irreversibility rate I=Wrev−Wactual I=339.84−195=144.84 kW

An ideal heat engine receives heat from a source at 1250 K at a rate of 450 kW and rejects heat to a medium at $33^{\circ} C$ . The power output of the engine is 195 kW. The irreversibility rate associated is

The correct option is A 144.84 kW
$η_{C a r n o t} = η_{r e v} = 1 - \frac{T_{L}}{T_{H}} = \frac{W_{r e v}}{Q_{s}}$

$W_{r e v} = (1 - \frac{(33 + 273)}{1250}) \times 450 = 339.84 k W$

$Irreversibility rate I = W_{r e v} - W_{a c t u a l}$

$I = 339.84 - 195 = 144.84 k W$