An ideal heat engine working between temperatures T1 and T2 has an efficiency η . The new efficiency if the temperatures of both the source and sink are doubled, will be
A
η2
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B
η
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C
2η
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D
3η
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Solution
The correct option is Bη
Efficiency of heat engine η=outputinput=T1−T2T1-------(a)
Now new efficiency of heat engine when sin and source temperature is doubledηnew=2T1−2T22T1